Answer by Lewis Kelsey for Why is the Dirac delta used when sampling...
If you decided to represent a time domain sample as an infinitesimal width sinc with main lobe width of $\frac{\pi}{T}$ at a fixed height $A$ centered at $t=0$, instead of a Dirac delta $A\delta(t)$,...
View ArticleAnswer by Sebastian Loeda for Why is the Dirac delta used when sampling...
I am unsatisfied with the answers provided thus far. This is a better explanation.The sampling process is actually the integral over the time period of the signal multiplied by the Dirac delta...
View ArticleAnswer by David for Why is the Dirac delta used when sampling continuous...
The best explanation of this that I've seen is from the "Digital Signal Processing Handbook" by Madisetti. Essentially the multiplication by the delta function is equivalent to sampling because the...
View ArticleAnswer by robert bristow-johnson for Why is the Dirac delta used when...
The answer to your question is that multiplying by the Dirac comb thus:$$ \begin{align}x(t) \cdot \sum_{n=-\infty}^{+\infty} \delta(t - nT) & = \sum_{n=-\infty}^{+\infty} x(t) \delta(t - nT)...
View ArticleWhy is the Dirac delta used when sampling continuous signals?
Why is this the most widely accepted model of signal sampling?When multiplying the continuous signal value with the Dirac delta, we get an infinite value. However, if we perform convolution of our...
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